4k^2=10+2k

Solution for 4k^2=10+2k equation:

4k^2=10+2k

We move all terms to the left:

4k^2-(10+2k)=0

We add all the numbers together, and all the variables

4k^2-(2k+10)=0

We get rid of parentheses

4k^2-2k-10=0

a = 4; b = -2; c = -10;
Δ = b2-4ac
Δ = -22-4·4·(-10)
Δ = 164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{164}=\sqrt{4*41}=\sqrt{4}*\sqrt{41}=2\sqrt{41}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{41}}{2*4}=\frac{2-2\sqrt{41}}{8}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{41}}{2*4}=\frac{2+2\sqrt{41}}{8}
$